[Python] Checkio Solution 解答 – Index Power
Level:
Elementary
Problem:
You are given an array with positive numbers and a number N. You should find the N-th power of the element in the array with the index N. If N is outside of the array, then return -1. Don’t forget that the first element has the index 0.
Let’s look at a few examples:
– array = [1, 2, 3, 4] and N = 2, then the result is 32 == 9;
– array = [1, 2, 3] and N = 3, but N is outside of the array, so the result is -1.
Input: Two arguments. An array as a list of integers and a number as a integer.
Output: The result as an integer.
Precondition: 0 < len(array) ≤ 10
0 ≤ N
all(0 ≤ x ≤ 100 for x in array)
Source: https://py.checkio.org
My Solution:
1 2 3 4 5 |
def index_power(array, n): if n < len(array): return array[n] ** n else: return -1 |
Comment:
Again, it’s like the exercise on Codecademy. =)