[Python] Checkio Solution 解答 – The Most Numbers

架網編程

Problem:

You are given an array of numbers (floats). You should find the difference between the maximum and minimum element. Your function should be able to handle an undefined amount of arguments. For an empty argument list, the function should return 0.

Floating-point numbers are represented in computer hardware as base 2 (binary) fractions. So we should check the result with ±0.001 precision.
Think about how to work with an arbitrary number of arguments.

 

Level:

Elementary

 

Input:

An arbitrary number of arguments as numbers (int, float).

 

Output:

The difference between maximum and minimum as a number (int, float).

 

Precondition:

0 ≤ len(args) ≤ 20
all(-100 < x < 100 for x in args)
all(isinstance(x, (int, float)) for x in args)

 

Source: https://py.checkio.org


My Solution:

def checkio(*args): 
  if len(args)>1: 
    return max(args) - min(args) 
  else: 
    return 0

Comment:

The solution is unexpectedly simple and short. Before I didn't understand what array is but then I found that the array here was actually tuple.

發佈日期:2017年9月22日 | 作者:橘小佑

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